Re: [Boost-users] [test] User objects with BOOST_CHECK_EQUAL

From: Gennadiy Rozental (rogeeff_at_[hidden])
Date: 2008-05-05 00:59:37

I believe template resolution rules prohibit implicit conversion. You need to define operator<<, or use BOOST_TEST_DONT_PRINT_LOG_VALUE( Foo );

Gennadiy
  "Robert Dailey" <rcdailey_at_[hidden]> ???????/???????? ? ???????? ?????????: news:496954360805021435p6cbc5c60oadae02d7de234d96_at_mail.gmail.com...
  Yes, the streaming operator I ended up trying and it worked (after I posted), but one thing I left out in my original post was the fact that I had an overloaded casting operator to std::string, which I figured would fix the issue just as well as the stream operator would. I was wrong, and that is what motivated me originally to post.

  As far as this problem is concerned, however, it's solved.

  On Fri, May 2, 2008 at 3:36 PM, Sohail Somani <sohail_at_[hidden]> wrote:

    Robert Dailey wrote:
    [snip]

    > Anyway, I have a class named "Foo", and I've given it an overloaded
    > boolean == operator. When I do the following, it fails to compile under
    > MSVC9:

    Dude, read the error:

    [snip]

    > 1>c:\it\tfs\crusades\sdks\boost\boost\test\test_tools.hpp(342) : error
    > C2679: binary '<<' : no operator found which takes a right-hand operand
    > of type 'const Foo' (or there is no acceptable conversion)

    No operator<< not ==. Boost test has something like this for
    CHECK_EQUAL(a,b):

    if(a!=b) { cout << "omg a!=b [a=" << a << ", b=" << b << "]" }

    --
    Sohail Somani
    http://uint32t.blogspot.com
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