Re: [Boost-users] serialization of accumulators available?

From: Robert Ramey (ramey_at_[hidden])
Date: 2008-06-27 15:08:34

Might I suggest that the interested parties offer to pay Eric/BoostPro
for this kind of effort?

a) It doesn't sound like a trivial task
b) I suspect it would cost less than each party rolling its own
c) It would likely get done sooner
d) with documentation
e) and tests
f) if it were rolled into the "official" accumulators library you would
probably get free testing and ongoing maintenance.
g) I'm sure interested parties would get acknowledgement
of support in the documentation - along with a free link to
the companies home page. Having your company associated
with boost in this manner could pay big dividends in
attracting and hiring future programmers.

Seems like a no-brainer to me.  But then I don't work
within a large organization.

Robert Ramey

Eric Niebler wrote:
> Sebastian Weber wrote:
>> I'm just starting to use the accumulators package. Cool library btw!
>> I was just wondering if there is some sort of serialization
>> available for the accumulators package. I guess it is for sure
>> possible to somehow serialize the accumulator_set or their
>> corresponding set of extractor objects such that all defined
>> statistics end up being serialized. Is there something available or
>> planned like this? Thanks in advance!
>
> Hi Sebastian,
>
> There is currently no serialization support in Boost.Accumulators, but
> it would certainly be a useful addition. There are a number of people
> in industry who have a vested interest in Boost.Accumulators, and
> after you sent your message they contacted me about possibly adding
> serialization support at some point in the future. So consider it on
> the ToDo list. I can't give you an ETA, so if you need something in
> the short term, I'm afraid you'll have to roll your own solution. If
> you go that route, you'll need to make each individual accumulator
> serializable and use the accumulator_set's visitation interface to
> serialize each accumulator in the set.
>
> HTH,