Re: [Boost-users] [boost-users][lambda] calling a functor in-place

From: Igor R (boost.lists_at_[hidden])
Date: 2008-07-17 10:09:03

>  typedef boost::function<void(void)> functor;
>  std::vector<functor> functors;
>  ...
>  using namespace boost::lambda;
>  std::for_each(
>    functors.begin(), functors.end(),
>    bind(&functor::operator(),_1));

Oh, I see... So the explicit bind is unavoidable :(. Is there any
reason for this? After all, lambda allows compact expressions like _1
= 1 , so why wouldn't it allow _1() ?