Re: [Boost-users] [boost-users][lambda] calling a functor in-place

From: Eric MALENFANT (Eric.Malenfant_at_[hidden])
Date: 2008-07-17 10:30:06

Igor R [boost.lists_at_[hidden]], le 17 juillet 2008 10:09:
>>  typedef boost::function<void(void)> functor;
>>  std::vector<functor> functors;
>>  ...
>>  using namespace boost::lambda;
>>  std::for_each(
>>    functors.begin(), functors.end(),
>>    bind(&functor::operator(),_1));
> 
> Oh, I see... So the explicit bind is unavoidable :(. 

As shown here: http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lambda.function_pointers_as_targets, the bind() is unavoidable, but it does not have to be that explicit. This should work:

  std::for_each(functors.begin(), functors.end(), bind(_1));

Note that Lambda may be unable to deduce the return type for some functors. See http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lambda.function_objects_as_targets for more information.

Éric Malenfant
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