Re: [Boost-users] [boost-users][lambda] calling a functor in-place

From: Igor R (boost.lists_at_[hidden])
Date: 2008-07-17 11:06:02

Great, thanks a lot to both of you!

> > > As shown here:
> http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lambda.function_pointers_as_targets,
> the bind() is unavoidable, but it does not have to be that explicit. This
> should work:
> > >  std::for_each(functors.begin(), functors.end(),
> bind(_1));
> > >
> >
> > Cute! Hadn't realized the first argument of bind can also be filled by a
> > placeholder.
> >
> > Joaquín M López Muñoz
> > Telefónica, Investigación y Desarrollo
> >
> >
>
> With Boost.Bind, however, the same trick does not work:
>
>  std::for_each(
>   functors.begin(), functors.end(),
>   boost::bind(::_1));
>
> This does not invoke operator() on the functor objects.