Re: [Boost-users] [boost-users][lambda] calling a functor in-place

From: joaquin_at_[hidden]
Date: 2008-07-17 10:37:02

joaquin_at_[hidden] escribió:
> Eric MALENFANT escribió:
>   
>> As shown here: 
>> http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lambda.function_pointers_as_targets, 
>> the bind() is unavoidable, but it does not have to be that explicit. 
>> This should work:
>>   std::for_each(functors.begin(), functors.end(), bind(_1));
>>
>>
>>     
>
> Cute! Hadn't realized the first argument of bind can also be filled by a
> placeholder.
>
> Joaquín M López Muñoz
> Telefónica, Investigación y Desarrollo
>   

With Boost.Bind, however, the same trick does not work:

  std::for_each(
    functors.begin(), functors.end(),
    boost::bind(::_1));

This does not invoke operator() on the functor objects.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo