Re: [Boost-users] [Function] Takes functor by value not reference?

Subject: Re: [Boost-users] [Function] Takes functor by value not reference?
From: Jeff Schwab (jeff_at_[hidden])
Date: 2010-02-14 13:00:38

Alexander Lamaison wrote:
> I may be misunderstanding as the boost::function code is tricky to follow
> but it seems to me that the function contructor takes the functor it is
> passed by value rather than by reference.
> 
> This requires the functor to be copyable.  In my case I'm trying to pass a
> functor as its abstract supertype which prevents copying.  Is it not
> possible to take the functor my reference, thereby removing the need for
> copying?

Could you just use a Boost.Ref wrapper?  Rather than passing f, you 
would pass ref(f).