Re: [Boost-users] [Function] Takes functor by value not reference?

Subject: Re: [Boost-users] [Function] Takes functor by value not reference?
From: Alexander Lamaison (awl03_at_[hidden])
Date: 2010-02-14 13:08:30

On Sun, 14 Feb 2010 13:00:38 -0500, Jeff Schwab wrote:

> Alexander Lamaison wrote:
>> I may be misunderstanding as the boost::function code is tricky to follow
>> but it seems to me that the function contructor takes the functor it is
>> passed by value rather than by reference.
>> 
>> This requires the functor to be copyable.  In my case I'm trying to pass a
>> functor as its abstract supertype which prevents copying.  Is it not
>> possible to take the functor my reference, thereby removing the need for
>> copying?
> 
> Could you just use a Boost.Ref wrapper?  Rather than passing f, you 
> would pass ref(f).

That looks like it might be just what I need.  Thanks!