Re: [Boost-users] [Boost.Assign] list_of::range without an initial (single) element?

Subject: Re: [Boost-users] [Boost.Assign] list_of::range without an initial (single) element?
From: Thorsten Ottosen (nesotto_at_[hidden])
Date: 2010-06-16 13:22:37

Nat Goodspeed skrev:
> Thorsten Ottosen wrote:
> 
>>>> However, list_of<int>() inserts a default value (so that
>>>> list_of<int>().range(a).range(b) == {0,1,2,3,4}).  
>>
>> Maybe we should add
>>
>>    empty_list_of<int>()
>>
>> ? It's quite trivial to add.
> 
> Does list_of<T>() have a default value for its T parameter?

No, how could it?

> Maybe introduce no-params list_of<T>() to produce an empty list, while 
> list_of<T>(const T&) keeps its current implementation? That would seem 
> to behave intuitively in both cases...

Just to be clear, you want list_of() to be empty_list_of<*any type*>(), 
and for the type of the list to be deduced by the first argument:

   list_of()(42);

would be a list of ints with one value (42).

?

If so, I think this syntax is possible, but I am worried that the 
difference between list_of() and list_of<T>() is too subtle.

-Thorsten