Re: [Boost-users] [qi and lambda] Get wrong reaction of the qi::rule if I use lambda for the action

Subject: Re: [Boost-users] [qi and lambda] Get wrong reaction of the qi::rule if I use lambda for the action
From: TONGARI (tongari95_at_[hidden])
Date: 2011-08-15 10:21:42

2011/8/15 TONGARI <tongari95_at_[hidden]>

> 2011/8/15 <boost_mailinglist_at_[hidden]>
>
> Hello,
>>
>> if I execute the following example, I get the following output "The bad
>> one The good one a" but I only expected "The good one a".
>>
>> Why does it happens?  Boost 1.47.0 was used.
>>
>>
>> #include <boost/config/warning_disable.**hpp>
>> #include <boost/spirit/include/qi.hpp>
>> #include <boost/lambda/lambda.hpp>
>>
>> #include <iostream>
>>
>> int main()
>> {
>>    using boost::spirit::qi::char_;
>>    using boost::spirit::qi::parse;
>>
>>    char const *first = "{a}", *last = first + std::strlen(first);
>>
>>    parse(first, last, '{' >> char_("a")[std::cout << "The good one " <<
>> boost::lambda::_1 << '\n'] |
>>        char_("b")[std::cout << "The bad one " << boost::lambda::_1 <<
>> '\n'] >> '}');
>>
>>    return 0;
>> }
>>
>
> Because  (std::cout << "The good one ") & (std::cout << "The bad one ") are
> not lambda expressions so they are executed immediately, and it seems
> Boost.Lambda just happened to work here.
>
> The corrected version would be:
>
> #include <boost/config/warning_disable.hpp>
> #include <boost/spirit/include/qi.hpp>
> #include <boost/spirit/include/phoenix.hpp>
>
>
> #include <iostream>
>
> int main()
> {
>    using boost::spirit::qi::char_;
>    using boost::spirit::qi::parse;
>    using boost::spirit::qi::_1;
>    using boost::phoenix::val;
>
>
>    char const *first = "{a}", *last = first + std::strlen(first);
>
>    parse(first, last, '{' >> char_("a")[std::cout << phx::val("The good one
> ") << _1 << '\n'] |
>        char_("b")[std::cout << phx::val("The bad one ") << _1 << '\n'] >>
> '}');
>
>    return 0;
> }
>

Please omit phx:: before val.