Boost Users :
Subject: Re: [Boost-users] begin (cout) or boost::copy to cout
From: Nathan Ridge (zeratul976_at_[hidden])
Date: 2011-09-13 20:41:18
> This function eliminats the need of passing explicit template parameters to
> std:: ostream_iterator, which makes the code fragile and hard to read.
I agree that having to pass a template parameter to std::ostream_iterator
However, overloading boost::begin for std::ostream is not a good solution,
because, as Steven pointed out, ostream is not a range. (And certainly,
overloading boost:copy for something as specific as std::ostream is
not a good solution - it goes directly against the spirit of generic
programming, which is to express algorithms in terms of a generic
interface (iterators), and have data structures adapt to that interface).
A better solution is to write a polymorphic version of ostream_iterator;
that is, a version that's not a template, but which has a templated
operator=, so that you can output any type using the iterator.
With such a modified ostream_iterator, you can write:
boost:copy(some_range, my_ostream_iterator(cout, " "));
which is very close to what you are aiming for.
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