Re: [Boost-users] [Phoenix] expression does not name a type

Subject: Re: [Boost-users] [Phoenix] expression does not name a type
From: Gordon Woodhull (gordon_at_[hidden])
Date: 2011-09-22 18:19:47

On Sep 22, 2011, at 2:12 PM, Júlio Hoffimann wrote:

> Dear all,
> 
> I can't understand why this test case is not compiling:
> 
> #include    <boost/function.hpp>
> #include    <boost/phoenix/core/argument.hpp>
> #include    <boost/phoenix/operator.hpp>
> #include    <iostream>
>  
> using namespace boost::phoenix::placeholders;
> expression::argument<1>::type X;
try

typename boost::phoenix::expression::argument<1>::type X;

or something equivalent
>  
> int main ( int argc, char *argv[] )
> {
>     boost::function<int(int)> f;
>     f = if_else( X == 0, X, X*2 );
>     std::cout << f(0) << f(12) << std::endl;
>     return 0;
> }  // ----------  end of function main  ----------
> The error message says 'expression' does not name a type. I've tried to explicitly play with boost::phoenix namespaces, but doesn't work.

HTH,
Gordon