Re: [Boost-users] [Phoenix] expression does not name a type

Subject: Re: [Boost-users] [Phoenix] expression does not name a type
From: Júlio Hoffimann (julio.hoffimann_at_[hidden])
Date: 2011-09-22 20:09:41

Hi Gordon,

Thank you for your reply. Incredibly, somehow, i forget to combine the
boost::phoenix namespace. I think i did it mentally, but forget to compile.
:-P

Regards,
Júlio.

2011/9/22 Gordon Woodhull <gordon_at_[hidden]>

>
> On Sep 22, 2011, at 2:12 PM, Júlio Hoffimann wrote:
>
> Dear all,
>
> I can't understand why this test case is not compiling:
>
> #include    <boost/function.hpp>#include    <boost/phoenix/core/argument.hpp>#include    <boost/phoenix/operator.hpp>#include    <iostream>
>  using namespace boost::phoenix::placeholders;
> expression::argument<1>::type X;
>
> try
>
> typename boost::phoenix::expression::argument<1>::type X;
>
> or something equivalent
>
>  int main ( int argc, char *argv[] ){
>     boost::function<int(int)> f;
>     f = if_else( X == 0, X, X*2 );
>     std::cout << f(0) << f(12) << std::endl;
>     return 0;}  // ----------  end of function main  ----------
>
> The error message says 'expression' does not name a type. I've tried to explicitly play with boost::phoenix namespaces, but doesn't work.
>
>
> HTH,
> Gordon
>
>
>
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