Re: [Boost-users] [gil] metafunction for layout

Subject: Re: [Boost-users] [gil] metafunction for layout
From: Lubomir Bourdev (lbourdev_at_[hidden])
Date: 2011-11-16 18:58:54

Hi Mark,

Luminosity is a single channel, and single-channel images in GIL are specified using a gray_layout_t layout. It doesn't make sense to keep the layout of the destination view; in fact you should require that the destination view is a single channel view (i.e. has a gray_layout_t layout)

Lubomir

On Nov 16, 2011, at 2:35 PM, Sapp, Mark wrote:

Hi All,

The following code is straight out of the tutorial about making function generic. Can anyone suggest how I might determine the layout of DstView here so that I can build an image of the same layout? In this example they hardcode gray_layout_t and I’m not seeing any metafunctions that return the layout.

template <typename SrcView, typename DstView>
void x_luminosity_gradient(const SrcView& src, const DstView& dst) {
    typedef typename channel_type<DstView>::type d_channel_t;
    typedef typename channel_convert_to_unsigned<d_channel_t>::type channel_t;
    typedef typename image_type<channel_t, gray_layout_t>::type gray_image_t;
    typedef typename gray_image_t::value_type gray_pixel_t;

    gray_image_t ccv_image(src.dimensions());
    copy_and_convert_pixels(src, view(ccv_image));
    x_gradient(const_view(ccv_image), dst);
}

Thanks,
Mark

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