Re: [Boost-users] [Regex] Is it possible to match any "linebreak"

Subject: Re: [Boost-users] [Regex] Is it possible to match any "linebreak"
From: John Maddock (boost.regex_at_[hidden])
Date: 2012-03-22 12:12:17

>>> Is there a way to have a regex like
>>>   [[:digit:]]{3}([^\n]+)\n?
>>> have \n match any line breaking character?
>>> (The processed files might have Unix or DOS line endings.)
>>
>> Use \R, see:
>>
> http://www.boost.org/doc/libs/1_49_0/libs/regex/doc/html/boost_regex/syntax/perl_syntax.html#boost_regex.syntax.perl_syntax.matching_line_endings
>>
>> HTH, John.
>
> Thank you John.
> Somehow I must have overlooked \R in the docs.
>
> However, I still have one issue with \R.
> In the following code everything works fine if I use r2.
> If  r1 the matches' captures do contain the newlines.
>
> In short: ([^\\R+]) does not seem to capture all non-linebreak characters.
> Should it? Or is this just a misunderstanding on my part?

No you can't do that, \R isn't a character class, it's much more complex 
than that - look at the link above to see what it maps to - something like 
[^\x0A-\x0D\x85\x{2028}\x{2029}] would be closer to the inverse.

HTH, John.