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Subject: Re: [Boost-users] [Bind] Understanding protect
From: Igor R (boost.lists_at_[hidden])
Date: 2012-03-27 14:25:00

>> bind(f, 1);
>  Yeah, but that doesn't quite fit the bill! Ultimately I'm doing this for each member of a
> range, via std algorithm, so I need to bind a unary argument to produce a nullary function
> object, which I can then pass to an evaluation context, ie my g( ) function.
> If I've generated the function object with bind and placeholder(s), it seems there's no way to
> prevent the binding of the last placeholder from triggering evaluation, when what I require is an unevaluated nullary function object.

I don't understand why you need a placeholder there. Could you provide
a trivial example that demonstrates what you mean exactly?
Again, the following creates a nullary functor.

void f( int i )
auto functor = boost::bind(&f, 12345);
// it can be now invoked:

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