Re: [Boost-users] [Bind] Understanding protect

Subject: Re: [Boost-users] [Bind] Understanding protect
From: Gordon Woodhull (gordon_at_[hidden])
Date: 2012-03-27 14:25:48

On Mar 27, 2012, at 2:13 PM, Robert Jones wrote:
> Ultimately I'm doing this for each member of a
> range, via std algorithm, so I need to bind a unary argument to produce a nullary function
> object, which I can then pass to an evaluation context, ie my g( ) function. If I've generated
> the function object with bind and placeholder(s), it seems there's no way to prevent the binding
> of the last placeholder from triggering evaluation, when what I require is an unevaluated nullary
> function object.

Hmm, works for me, IIUC:

#include <boost/bind.hpp>
#include <iostream>

template<typename F>
void g(F const &f) {
  f();
}

void f(int x) {
  std::cout << "x is " << x << std::endl;
}

int main() {
  for(int i=0; i<7; ++i)
    g(boost::bind(f,i));
  return 0;
}