Re: [Boost-users] [Boost.Integer] On Win32, boost::uint_t<65>::fast has 64 bits?

Subject: Re: [Boost-users] [Boost.Integer] On Win32, boost::uint_t<65>::fast has 64 bits?
From: Scott Meyers (NeverRead_at_[hidden])
Date: 2012-05-02 01:46:18

On 5/1/2012 10:40 PM, Steven Watanabe wrote:
> Obviously this isn't going to work unless the compiler supports a
> 128-bit int.  I suppose it would be better to cause a compile error
> if there isn't a sufficiently wide integer type.

That's what it's documented to do.  Here's the full spec for
boost::uint_t<N>::fast :

> The easiest-to-manipulate, built-in, unsigned integral type with at
> least N bits. The parameter should be a positive number. A
> compile-time error results if the parameter is larger than the number
> of bits in the largest integer type.

If I change 65 to 66, the code fails to compile. Can something this
simple really be a bug in the library?  Yes, I know, I could check the
source code, but I'm being lazy right now.  If this is not a clear case
of pilot error, I'll take a look.

Thanks,

Scott