Re: [Boost-users] [Boost.Integer] On Win32, boost::uint_t<65>::fast has 64 bits?

Subject: Re: [Boost-users] [Boost.Integer] On Win32, boost::uint_t<65>::fast has 64 bits?
From: John Maddock (boost.regex_at_[hidden])
Date: 2012-05-02 03:21:05

> The type yielded by boost::uint_t<N>::fast seems pretty clear: "The 
> easiest-to-manipulate, built-in, unsigned integral type with at least N 
> bits."
>
> But when I run the following program, which prints the number of bits in 
> the type returned by boost::uint_t<65>::fast (i.e., a type with at least 
> 65 bits), I get 64.
>
> #include <iostream>
> #include <climits>
> #include <boost/integer.hpp>
>
> int main()
> {
>   std::cout << "boost::uint_t<65>::fast has "
>             << CHAR_BIT * sizeof(boost::uint_t<65>::fast)
>             << " bits\n";
> }
>
>
> I get the same results with VC10, VC11 beta, and gcc 4.7 on Win32 with 
> Boost 1.49.  I must be doing something wrong, right? But what?

I seem to remember fixing that as a bug fairly recently - what Boost version 
are you using?

John.