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Subject: [Boost-users] [BGL] isomorphism: how to define vertex invariant
From: Pablo Madoery (madoerypablo_at_[hidden])
Date: 2014-02-19 10:44:44
Hi, I have two graphs and I want to know if they are isomorphic.
I adjunct the graphs in .png. I read the documentation but i can't figure
out how i must define the vertex invariant correctly. what I want is to
consider that two graph are not isomorphic taking count of the vertices ids
(the unsigned int value that they have).
In the example i give I want the function isomorphism to return false.
actually it return true.
Thank you !
////////////////////////////////////////////////////////////////////////////////////////////
Graph graph1;
Graph::vertex_descriptor aA = add_vertex(graph1);
Graph::vertex_descriptor bA = add_vertex(graph1);
Graph::vertex_descriptor cA = add_vertex(graph1);
Graph::edge_descriptor edA1 = (add_edge(aA, bA, graph1)).first;
Graph::edge_descriptor edA2 = (add_edge(bA, cA, graph1)).first;
graph1[edA1].weight = 1;
graph1[edA2].weight = 2;
////////////////////////////////////////////////////////////////////////////////////////////
Graph graph2;
Graph::vertex_descriptor aB = add_vertex(graph2);
Graph::vertex_descriptor bB = add_vertex(graph2);
Graph::vertex_descriptor cB = add_vertex(graph2);
Graph::edge_descriptor edB1 = (add_edge(bB, aB, graph2)).first;
Graph::edge_descriptor edB2 = (add_edge(aB, cB, graph2)).first;
graph2[edB1].weight = 1;
graph2[edB2].weight = 2;
///////////////////////////////////////////////////////////////////////////////////////////
bool isIso = boost::isomorphism(graph1, graph2);
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