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Subject: Re: [Boost-users] [EXTERNAL] Re: Boost Units initialize quantity with signaling NaN
From: Belcourt, Kenneth (kbelco_at_[hidden])
Date: 2016-08-13 15:38:14
> On Aug 13, 2016, at 10:56 AM, Steven Watanabe <watanabesj_at_[hidden]> wrote:
>
> AMDG
>
> On 08/10/2016 08:55 PM, Belcourt, Kenneth wrote:
>>
>> Iâm trying to find a way to initialize a Boost Unit with a signaling NaN, not just a NaN with the signal cleared. It seems that the only way to initialize a quantity is by multiplying by the unit, and that multiplication clears the signal on the NaN. I know I can just modify the quantity.hpp header and initialize the default constructor val_ member with the signaling NaN, but I was hoping for a cleaner solution.
>>
>> Hereâs an example (typed in by hand, not tested):
>>
>> const double s_nan = std::numeric_limits<double>::signaling_NaN();
>>
>> typedef quantity<si::acceleration, double> acceleration_t;
>> BOOST_UNITS_STATIC_CONSTANT(acceleration_u, acceleration);
>>
>> acceleration_t a(s_nan * acceleration_u); // <â this clears the signal on the NaN
>>
>> Has anyone encountered this or know of a more elegant solution than modifying the quantity.hpp header?
>>
>
> I can't reproduce the problem with VS 2015.
>
> #include <boost/units/quantity.hpp>
> #include <limits>
> #include <boost/units/systems/si.hpp>
> #include <iostream>
>
> using boost::units::quantity;
> namespace si = boost::units::si;
>
> int main() {
> quantity<si::length> x(std::numeric_limits<double>::signaling_NaN()
> * si::meter);
> std::cout << std::hex << *(unsigned long long*)&x << std::endl;
> return 0;
> }
>
> prints 7ff8000000000001
>
> Multiplication by a unit (as opposed to
> a quantity) does not require a floating
> point multiplication. It only copies the
> value around. I have no idea why you're
> seeing the signal bit being cleared.
I wonder if copying is somehow causing problems. I see this:
Copying a NaN may not preserve its bit representation.
mentioned here:
http://en.cppreference.com/w/cpp/types/numeric_limits/signaling_NaN
Perhaps thatâs our problem.
Thanks for the help Steven.
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