Re: [Boost-users] Enquiry on boost.geometry and intersection()

Subject: Re: [Boost-users] Enquiry on boost.geometry and intersection()
From: Adam Wulkiewicz (adam.wulkiewicz_at_[hidden])
Date: 2018-11-16 03:30:21

Hi and welcome,

Zhang Qun Via Boost-users wrote:
> Hi guys, first-time post here. Hello to everyone.
>
> I'm using boost.geometry to implement a project. I need to calculate 
> the intersection between a line and a polygon. I know there is no 
> infinite line concept in boost.geometry. So I try to use the segment 
> to intersect with a polygon, however, it seems not supported yet. Is 
> there any other workaround that I can implement the intersection 
> between a line and a polygon? The line is like y=mx+b or ax + by + c = 0.
>

Indeed the intersection of segment and polygon does not compile even 
though it should. Fortunately you can represent a segment as a 
linestring with 2 points. Something like this:

namespace bg = boost::geometry;

typedef bg::model::point<double, 2, bg::cs::cartesian> point;
typedef bg::model::box<point> box;
typedef bg::model::segment<point> segment;
typedef bg::model::linestring<point> linestring;
typedef bg::model::multi_linestring<linestring> multi_linestring;
typedef bg::model::polygon<point> polygon;

// create some polygon, a circle
polygon poly;
for (double a = 0; a < 2 * 3.14; a += 0.1)
 Â Â Â  bg::append(poly, point(cos(a), sin(a)));
// correct data to match compile-time metadata
// (clockwise, closed polygon)
bg::correct(poly);

// calculate polygon's bounding box which could be used with line
// equation to calculate segment's endpoints
box b = bg::return_envelope<box>(poly);

// here you could calculate a segment represented as linestring
// using min and max coordinates of polygon's envelope
// and line's parameters
// but for now:
linestring ls;
bg::append(ls, point(-1, -1));
bg::append(ls, point(1, 1));

// the result of the intersection of linear and areal geometry
// is multi-linestring
multi_linestring result;
bg::intersection(ls, poly, result);

std::cout << bg::wkt(ls) << std::endl;
std::cout << bg::wkt(poly) << std::endl;
std::cout << bg::wkt(result) << std::endl;

Regards,
Adam