Date: 2000-12-01 12:37:59
--- In boost_at_[hidden], Kevlin Henney <kevlin_at_c...> wrote:
> In message <90876s+i8vd_at_e...>, d.frey_at_g... writes
> >/* How to specialize for T == S ???
> >template< typename U > template<> U lexical_cast< U, U >( U arg )
> > cout << "X.";
> > return arg;
> Requires partial function template specialisation, which we don't
> in the language. You can overload but not specialise.
Hm. Too bad... :(
> >// This only work for lexical_cast's argument being declared as 'S
> >arg' and not 'const S& arg'
> >template<> string lexical_cast< string, const char* >( const char*
> > cout << "3.";
> > return string( arg );
> Did you also try this with const char *& rather than plain const
Yes, but I didn't get the compiler to accept it. Probably my fault or
it's the gcc... I'll try it again on Monday, when I'm back at the
Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk