From: Dave Harris (brangdon_at_[hidden])
Date: 2005-05-19 15:14:44
technews_at_[hidden] (Jonathan Turkanis) wrote (abridged):
> > Are we going to generalise it to allow any (compile-time constant)
> > terminator?
> Why does the terminator have to be a compile-time constant?
I was hesitant about suggesting a generalisation which added run-time
overhead over only supporting '\0'.
Also, the need is not very common in my experience.
-- Dave Harris, Nottingham, UK.