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From: dan marsden (danmarsden_at_[hidden])
Date: 2005-11-04 13:27:48
--- David Abrahams <dave_at_[hidden]> wrote:
>
> > Member pointer operator
> >
> > a->*member_object_pointer
> > a->*member_function_pointer
> >
> > The left hand side of the member pointer operator
> must be an actor
> > returning a pointer type. The right hand side of
> the member pointer
> > operator may be either a pointer to member object
> or pointer to
> > member function.
> >
> >
> > If the right hand side is a member object pointer,
> the result is a
> > composite providing lazy access to that member.
>
> "an actor that, when invoked, returns a reference
> to that member."
I agree, clearer than my wording, I'll fix that.
>
> > For example:
> >
> > struct A
> > {
> > int member;
> > };
> >
> > A* a = new A;
> > ...
> >
> > (arg1->*&A::member)(a); // returns member
> a->member
> >
> > If the right hand side is a member function
> pointer, the result is a
> > delayed function call. The arguments to this call
> are then bound to
> > the returned composite.
>
> The wording is confusing. "Delayed function call"
> has not been
> defined. Why not just say that "the result is an
> actor that, when
> invoked, calls the specified member function?" Is
> that inaccurate?
>
I think it probably should say that as well, I agree
its clearer.
Thanks for the feedback.
Dan
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