Re: [boost] [accumulators] why not operator+=?

Subject: Re: [boost] [accumulators] why not operator+=?
From: Rodolfo Lima (rodolfo_at_[hidden])
Date: 2009-01-30 17:13:14

Neal Becker escreveu:
> Not sure what you mean by addition.  Here, we are 'adding' a new sample (or 
> samples) to the collection of samples.  It doesn't matter whether the 
> underlying accumulator then uses 'addition' or not.  Seems clear to me.

Why not use operator<< like std::ostream uses? It implies something
getting into something else, just the case here (IMHO).

[]s,
rod