Boost Users :
From: Foster, Gareth (gareth.foster_at_[hidden])
Date: 2005-01-05 13:38:49
> I know it's confusing. Most C++ programmers never see a function type
> in the wild. You can use remove_pointer to turn a pointer-to-function
> into a function.
Could I do ...
int (int) * p_my_function_pointer;
Or some other such madness? I'm reading MSDN about the indirection operator
at the moment, maybe that will help to clear this up in my head. Can you
recommend a page on "function types".
-- Dave Abrahams Boost Consulting http://www.boost-consulting.com _______________________________________________ Boost-users mailing list Boost-users_at_[hidden] http://lists.boost.org/mailman/listinfo.cgi/boost-users
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