Boost Users :
From: David Abrahams (dave_at_[hidden])
Date: 2005-01-05 14:25:26
Foster, Gareth wrote:
>> I know it's confusing. Most C++ programmers never see a function type
>> in the wild. You can use remove_pointer to turn a pointer-to-function
>> into a function.
> Could I do ...
> int (int) * p_my_function_pointer;
> Or some other such madness?
Yes, some other. The "*" and variable name goes in between the return
type and the parameter list if you're declaring a function pointer:
int (*p_my_function_pointer) (int)
> I'm reading MSDN about the indirection operator
> at the moment, maybe that will help to clear this up in my head. Can you
> recommend a page on "function types".
-- Dave Abrahams Boost Consulting http://www.boost-consulting.com
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