Re: [Boost-users] [boost-users][lambda] calling a functor in-place

From: joaquin_at_[hidden]
Date: 2008-07-17 10:34:39

Eric MALENFANT escribió:
> Igor R [boost.lists_at_[hidden]], le 17 juillet 2008 10:09:
>   
>>>  typedef boost::function<void(void)> functor;
>>>  std::vector<functor> functors;
>>>  ...
>>>  using namespace boost::lambda;
>>>  std::for_each(
>>>    functors.begin(), functors.end(),
>>>    bind(&functor::operator(),_1));
>>>       
>> Oh, I see... So the explicit bind is unavoidable :(.
>>     
>
> As shown here: http://www.boost.org/doc/libs/1_35_0/doc/html/lambda/le_in_details.html#lambda.function_pointers_as_targets, the bind() is unavoidable, but it does not have to be that explicit. This should work:
>
>   std::for_each(functors.begin(), functors.end(), bind(_1));
>
>   

Cute! Hadn't realized the first argument of bind can also be filled by a 
placeholder.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo