From: Synge Todo (wistaria_at_[hidden])
Date: 2004-07-21 07:25:46
From: David Abrahams <dave_at_[hidden]>
Date: Wed, 21 Jul 2004 07:20:20 -0400
> > I am a bit confused. Can "using std::pow;" be accepted by the
> > compilers without a declaration of std::pow?
> No it can't.
Thank you, David. It means that we have to always include <cmath>
beforehand whenever we include Boost.Random headers, since it contains
a line declaring "using std:pow;". This applies even if we just
include Boost.Random headers without any instantiation of Boost.Random
class templates. Isn't this requirement too strong for users???
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