From: David Abrahams (dave_at_[hidden])
Date: 2004-07-21 07:47:11
Synge Todo <wistaria_at_[hidden]> writes:
> From: David Abrahams <dave_at_[hidden]>
> Date: Wed, 21 Jul 2004 07:20:20 -0400
>> > I am a bit confused. Can "using std::pow;" be accepted by the
>> > compilers without a declaration of std::pow?
>> No it can't.
> Thank you, David. It means that we have to always include <cmath>
> beforehand whenever we include Boost.Random headers, since it contains
> a line declaring "using std:pow;". This applies even if we just
> include Boost.Random headers without any instantiation of Boost.Random
> class templates. Isn't this requirement too strong for users???
Yes. Boost.Random should #include <cmath> itself.
-- Dave Abrahams Boost Consulting http://www.boost-consulting.com
Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk